Exam - BARTON COLLEGE PRACTICE PLACEMENT TEST Ex. 39
Exercise:
The inequality |8 - x| < 8 is equivalent to:
a) x < 0
b) x > 0
c) x<0 or x > 16
d) 0 < x < 16
Solution
Solve the absolute value inequality: |8 - x| < 8
We solve the inequality 8-x < 8 and the inequality -(8-x) < 8, and than find intersection between the solutions.
Solution 1 for (8-x) >=0
8 - x < 8
8 - 8 < x
x > 0
Solution 1 for (8-x) >=0
8 - x < 8
8 - 8 < x
x > 0
x > 0 and (8-x) >=0 is:
0 < x <= 8
Solution 2 for (8-x) <=0
-(8-x) < 8
-8 + x < 8
x < 8 + 8
x < 16
x <16 and (8-x) <=0 is 8 <= x < 16
The combination of solution 1 and 2 :
0 < x <= 8 OR 8 <= x < 16 is
0 < x < 16
The correct solution is d.
We can see the problem graphicaly:
The inequality |8 - x| < 8 is equivalent to 0 < x < 16 |
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